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squaresOfSortedArray.js
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76 lines (67 loc) · 2.18 KB
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// Given an array of integers A sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order.
// Example 1:
// Input: [-4,-1,0,3,10]
// Output: [0,1,9,16,100]
// Example 2:
// Input: [-7,-3,2,3,11]
// Output: [4,9,9,49,121]
// Note:
// 1 <= A.length <= 10000
// -10000 <= A[i] <= 10000
// A is sorted in non-decreasing order.
// O(nlog(n)) time | O(n) space
// const squaresOfSortedArray = (arr) => {
// return newArr = arr.map(el => Math.pow(el, 2)).sort();
// }
// o(n) time | O(n) space
const squaresOfSortedArray = (arr) => {
if (!arr.length) return [];
let positiveIdx = 0;
while (arr[positiveIdx] <= 0) {
positiveIdx++;
}
let negativeIdx = positiveIdx - 1;
let tempIdx = 0;
let res = [];
while (negativeIdx >= 0 && positiveIdx < arr.length) {
let negSquard = Math.pow(arr[negativeIdx], 2);
let posSquared = Math.pow(arr[positiveIdx], 2);
if (negSquard < posSquared) {
res[tempIdx] = negSquard;
negativeIdx--;
} else {
res[tempIdx] = posSquared;
positiveIdx++;
}
tempIdx++;
}
while (negativeIdx >= 0) {
res[tempIdx++] = Math.pow(arr[negativeIdx], 2);;
negativeIdx--;
}
while (positiveIdx < arr.length) {
res[tempIdx++] = Math.pow(arr[positiveIdx], 2);
positiveIdx++;
}
return res
}
const squaresOfSortedArray2 = (arr) => {
if (!arr.length) return [];
const sortedSquares = Array(arr.length).fill(0);
let left = 0;
let right = arr.length - 1;
for (let i = sortedSquares.length - 1; i >= 0; i--) {
if (Math.abs(arr[left] > arr[right])) {
sortedSquares[i] = Math.pow(arr[left], 2);
left++;
} else {
sortedSquares[i] = Math.pow(arr[right], 2);
right--;
}
}
return sortedSquares;
}
// console.log(squaresOfSortedArray([-4,-1,0,3,10])) // [0,1,9,16,100]
// console.log(squaresOfSortedArray([-7,-3,2,3,11])) // [4,9,9,49,121]
console.log(squaresOfSortedArray2([-4, -1, 0, 3, 10])) // [0,1,9,16,100]
console.log(squaresOfSortedArray2([-7, -3, 2, 3, 11])) // [4,9,9,49,121]