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reverse-odd-levels-of-binary-tree.java
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84 lines (66 loc) · 2.34 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode reverseOddLevels(TreeNode root) {
Queue<TreeNode> curr = new LinkedList<>();
ArrayList<ArrayList<TreeNode>> levels = new ArrayList<>();
int level = 0;
curr.add(root);
while (! curr.isEmpty()) {
int n = curr.size();
levels.add(new ArrayList<>());
List<TreeNode> nodes = new ArrayList<>();
for (int i = 0; i<n; i++) {
TreeNode node = curr.poll();
levels.get(level).add(node);
nodes.add(node);
if (node != null) {
curr.add(node.left);
curr.add(node.right);
}
}
level++;
}
// for (int i = 0; i<levels.size(); i++) {
// String s = "";
// for (TreeNode n: levels.get(i)) {
// s += (n != null ? n.val:-1) +" ";
// }
// System.out.println(s);
// }
for (int i = 0; i<levels.size(); i++) {
if (i%2 == 1) {
int a = 0;
int b = levels.get(i).size() - 1;
while (a < b) {
try {
int x = levels.get(i).get(a).val;
int y = levels.get(i).get(b).val;
levels.get(i).get(a).val = y;
levels.get(i).get(b).val = x;
// System.out.println("A");
}
catch (Exception e) {
}
a++;
b--;
}
}
}
return root;
}
}
// Submission Link: https://leetcode.com/problems/reverse-odd-levels-of-binary-tree/submissions/802550130/