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lis.py
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70 lines (55 loc) · 1.45 KB
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import math
def lis_aux(arr):
return lis_bf(arr,-math.inf,0)
def lis_bf(arr,prev,curr):
if curr == len(arr):
return 0
taken = 0
if arr[curr] > prev:
taken = 1 + lis_bf(arr,arr[curr],curr+1)
nontaken = lis_bf(arr,prev,curr+1)
return max(taken,nontaken)
def lis_memo_aux(arr):
d = [-1] * (len(arr)+1)
for i in range(len(arr)):
d[i] = [-1]*(len(arr))
return lis_memo(arr,-1,0,d)
def lis_memo(arr,prev,curr,d):
if curr == len(arr):
return 0
if d[prev+1][curr] >= 0:
return d[prev+1][curr]
taken = 0
if prev < 0 or arr[curr] > arr[prev]:
taken = 1 + lis_memo(arr,curr,curr+1,d)
nontaken = lis_memo(arr,prev,curr+1,d)
d[prev+1][curr] = max(taken,nontaken)
return d[prev+1][curr]
def lis(arr):
n = len(arr)
lis = [1]*n
prev = [0]*n
for i in range(0, n):
prev[i] = i
for i in range (1 , n):
for j in range(0 , i):
if arr[i] > arr[j] and lis[i]< lis[j] + 1:
lis[i] = lis[j]+1
prev[i] = j
maximum = 0
idx = 0
for i in range(n):
if maximum < lis[i]:
maximum = lis[i]
idx = i
seq = [arr[idx]]
while idx != prev[idx]:
idx = prev[idx]
seq.append(arr[idx])
return (maximum, reversed(seq))
arr = [5,2,8,6,3,6,9,7]
ans = lis(arr)
print("Longitud de LIS", ans[0])
print("Una LIS posible", ", ".join(str(x) for x in ans[1]))
'''print(lis_aux([5,2,8,6,3,6,9,7]))
print(lis_memo_aux([5,2,8,6,3,6,9,7]))'''