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binary_tree_maximum_path_sum.cpp
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79 lines (74 loc) · 3.12 KB
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#include <iostream>
#include <climits>
using namespace std;
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution {
public:
int maxPathSum(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (root == NULL) return 0;
int max_sum = INT_MIN;
maxSubSum(root, max_sum);
if (root->val > max_sum)
max_sum = root->val;
return max_sum;
// int result = root->val;
// if (root-> left != NULL && root->right != NULL) {
// int left = maxSubSum(root->left);
// int right = maxSubSum(root->right);
// if (left > result) result = left;
// if (right > result) result = right;
// if ((left + root->val) > result) result = left + root->val;
// if ((right + root->val) > result) result = right + root->val;
// if ((left + right + root->val) > result) result = left + right + root->val;
// } else if (root->left == NULL && root->right != NULL) {
// int right = maxSubSum(root->right);
// if (right > 0) result = max(right+root->val, right);
// else result = max(right, root->val);
// } else if (root->left != NULL && root->right == NULL) {
// int left = maxSubSum(root->left);
// if (left > 0) result = max(left+root->val, left);
// else result = max(left, root->val);
// }
// return result;
}
void maxSubSum(TreeNode *root, int &max_sum) {
if (!root) return;
else {
maxSubSum(root->left, max_sum);
maxSubSum(root->right, max_sum);
// find the max value in (root->val, root->left->val+root->val, root->right->val+root->val,
// root->val + root->right->val + root->left->val); which is mean the sum of maximum path which
// end with root
int left = 0, right = 0;
if (root->left) {
left = root->left->val;
}
if (root->right) {
right = root->right->val;
}
if (root->val + left + right > max_sum) max_sum = root->val + left + right;
if (left+root->val > max_sum) max_sum = root->val + left;
if (right+root->val > max_sum) max_sum = root->val + right;
if (root->val > max_sum) max_sum = root->val;
// root->val equals the sum of maximum path which will go through root
int left_sum = left + root->val;
int right_sum = right + root->val;
root->val = max(max(left_sum, right_sum), root->val);
}
// if (root->left == NULL && root->right == NULL) return root->val;
// else if (root->left != NULL && root->right != NULL) {
// return max(max(maxSubSum(root->left)+root->val, maxSubSum(root->right)+root->val), root->val);
// } else if (root->left == NULL && root->right != NULL) {
// return max(maxSubSum(root->right)+root->val, root->val);
// } else if (root->left != NULL && root->right == NULL) {
// return max(maxSubSum(root->left)+root->val, root->val);
// }
}
};