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75 changes: 75 additions & 0 deletions database/database.sql
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create table if not exists professor (
prof_id integer primary key,
prof_lname varchar(50),
prof_fname varchar(50)
);

create table if not exists student (
stud_id integer primary key,
stud_lname varchar(50),
stud_fname varchar(50),
stud_street varchar(255),
stud_city varchar(50),
stud_zip varchar(10)
);

create table if not exists enroll (
stud_id integer,
class_id integer,
grade enum ('A', 'B', 'C', 'D', 'F')
);

create table if not exists class (
class_id integer primary key,
class_name varchar(255),
prof_id integer,
course_id integer,
room_id integer
);

create table if not exists room (
room_id integer primary key,
room_loc varchar(50),
room_cap varchar(50),
class_id integer
);

create table if not exists course (
course_id integer primary key,
course_name varchar(255)
);

alter table
enroll
add
constraint fk_student_enroll foreign key (stud_id) references student(stud_id);

alter table
enroll
add
constraint fk_class_enroll foreign key (class_id) references class(class_id);

alter table
enroll
add
primary key (stud_id, class_id);

alter table
class
add
constraint fk_prof_class foreign key (prof_id) references professor(prof_id);

alter table
class
add
constraint fk_course_class foreign key (course_id) references course(course_id);

alter table
class
add
constraint fk_room_class foreign key (room_id) references room(room_id);

alter table
room
add
constraint fk_class_room foreign key (class_id) references class(class_id)
138 changes: 138 additions & 0 deletions database/query.sql
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## 1
## những cặp student-professor có dạy học nhau và số lớp mà họ có liên quan
select
concat(p.prof_fname, ' ', p.prof_lname) prof_name,
concat(s.stud_fname, ' ', s.stud_lname) stud_name,
count(*) number_of_classes
from
student s
join enroll e on s.stud_id = e.stud_id
join class c on c.class_id = e.class_id
join professor p on p.prof_id = c.prof_id
group by
prof_name,
stud_name;

## 2
## những course (distinct) mà 1 professor cụ thể đang dạy
select
distinct *
from
course
join class c on course.course_id = c.course_id
join professor p on c.prof_id = p.prof_id
where
p.prof_id = 1;

## 3
## những course (distinct) mà 1 student cụ thể đang học
select
distinct course.course_id,
course_name
from
course
join class c on course.course_id = c.course_id
join enroll e on c.class_id = e.class_id
join student s on e.stud_id = s.stud_id
where
e.stud_id = 5;

## 4
## điểm số trung bình của 1 học sinh cụ thể, quy ra lại theo chữ cái và học lực
select
case
when avg(score) >= 9 then 'A'
when avg(score) >= 7 then 'B'
when avg(score) >= 5 then 'C'
when avg(score) >= 3 then 'D'
else 'F'
end as avg_score,
case
when avg(score) >= 8 then 'GOOD'
when avg(score) < 5 then 'WEAK'
else 'AVERAGE'
end as ranked
from
enroll e1
join (
select
stud_id,
case
when grade = 'A' then 10
when grade = 'B' then 8
when grade = 'C' then 6
when grade = 'D' then 4
when grade = 'E' then 2
when grade = 'F' then 0
end as score
from
enroll
) e2 on e1.stud_id = e2.stud_id
where
e1.stud_id = 2
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Collaborator

@tpdongcs tpdongcs May 28, 2023

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because we know stud_id, why dont add it into the sub query ? so the number of rows need to be join can be reduced.

group by
e1.stud_id;

## 5
## điểm số trung bình của các class (quy ra lại theo chữ cái)
select
e1.class_id class_id,
case
when avg(score) >= 9 then 'A'
when avg(score) >= 7 then 'B'
when avg(score) >= 5 then 'C'
when avg(score) >= 3 then 'D'
else 'F'
end as avg_score
from
enroll e1
join (
select
class_id,
case
when grade = 'A' then 10
when grade = 'B' then 8
when grade = 'C' then 6
when grade = 'D' then 4
when grade = 'E' then 2
when grade = 'F' then 0
end as score
from
enroll
) e2 on e1.class_id = e2.class_id
group by
e1.class_id;

## 6
## điểm số trung bình của các course (quy ra lại theo chữ cái)
select
cre.course_id,
cre.course_name,
case
when avg(score) >= 9 then 'A'
when avg(score) >= 7 then 'B'
when avg(score) >= 5 then 'C'
when avg(score) >= 3 then 'D'
else 'F'
end as avg_score
from
enroll e1
join (
select
class_id,
case
when grade = 'A' then 10
when grade = 'B' then 8
when grade = 'C' then 6
when grade = 'D' then 4
when grade = 'E' then 2
when grade = 'F' then 0
end as score
from
enroll
) e2 on e1.class_id = e2.class_id
join class c on c.class_id = e1.class_id
join course cre on cre.course_id = c.course_id
group by
cre.course_id,
cre.course_name
158 changes: 158 additions & 0 deletions database/seed.sql
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# My data examples for the assignment
# Use at your own risk
INSERT INTO
professor (prof_id, prof_lname, prof_fname)
VALUES
(1, 'Smith', 'John'),
(2, 'Doe', 'Jane'),
(3, 'Johnson', 'Michael'),
(4, 'Williams', 'Emily'),
(5, 'Jones', 'David'),
(6, 'Garcia', 'Sophia');

INSERT INTO
student (
stud_id,
stud_lname,
stud_fname,
stud_street,
stud_city,
stud_zip
)
VALUES
(
1,
'Brown',
'Alice',
'123 Main St',
'Springfield',
'12345'
),
(
2,
'Davis',
'Bob',
'456 Elm St',
'Shelbyville',
'54321'
),
(
3,
'Miller',
'Charlie',
'789 Oak St',
'Capital City',
'67890'
),
(
4,
'Rodriguez',
'Daniel',
'246 Maple St',
'Ogdenville',
'24680'
),
(
5,
'Wilson',
'Emma',
'369 Pine St',
'North Haverbrook',
'36912'
),
(
6,
'Martinez',
'Olivia',
'159 Cedar St',
'Brockway',
'15975'
);

INSERT INTO
class (class_id, class_name, prof_id, course_id)
VALUES
(1, 'Intro to Computer Science', 1, 1),
(2, 'Calculus I', 2, 2),
(3, 'English Literature', 3, 3),
(4, 'Chemistry I', 4, 4);

INSERT INTO
room (room_id, room_loc, room_cap)
VALUES
(101, 'Building A', '30'),
(102, 'Building B', '40'),
(103, 'Building C', '35'),
(104, 'Building D', '45');

UPDATE
room
set
class_id = 1
where
room_id = 101;

UPDATE
room
set
class_id = 2
where
room_id = 102;

UPDATE
room
set
class_id = 3
where
room_id = 103;

UPDATE
room
set
class_id = 4
where
room_id = 104;

INSERT INTO
course (course_id, course_name)
VALUES
(1, 'Computer Science'),
(2, 'Mathematics'),
(3, 'English'),
(4, 'Chemistry');

INSERT INTO
enroll (stud_id, class_id, grade)
VALUES
(1, 1, 'A'),
(1, 2, 'B'),
(2, 1, 'C'),
(3, 2, 'A'),
(4, 1, 'B'),
(4, 2, 'A'),
(6, 2, 'C'),
(1, 3, 'A'),
(1, 4, 'B'),
(2, 3, 'C'),
(2, 4, 'A'),
(5, 1, 'C'),
(5, 2, 'A'),
(5, 6, 'A');

INSERT INTO
room (room_id, room_loc, room_cap)
VALUES
(105, 'Building E', '50'),
(106, 'Building F', '55');

INSERT INTO
class (
class_id,
class_name,
prof_id,
course_id,
room_id
)
VALUES
(5, 'History of Art', 5, 5, 105),
(6, 'Physics I', 6, 6, 106);
7 changes: 7 additions & 0 deletions leetcode/1393.Capital Gain Loss.sql
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select
stock_name,
sum(if(operation = 'Sell', price, - price)) as capital_gain_loss
from
stocks
group by
stock_name
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