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Fix ValueError crash in contact extraction when names have fewer than 2 spaces #144

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Fix ValueError crash in contact extraction when names have fewer than 2 spaces #144

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e2b136e
Initial plan
Copilot Jan 30, 2026
de47403
Fix critical ValueError bug in find_all_contacts() when parsing conta…
Copilot Jan 30, 2026
6e37978
Complete critical bug fix with verification and testing
Copilot Jan 30, 2026
f44b45b
Remove pycache files
Copilot Jan 30, 2026
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28 changes: 26 additions & 2 deletions ui_auto_wechat.py
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Original file line number Diff line number Diff line change
Expand Up @@ -215,7 +215,19 @@ def find_all_contacts(self) -> pd.DataFrame:
contact_set = set()
for contact in auto.ListControl(Depth=7).GetChildren():
# 获取用户的昵称备注以及标签。注意这种方式没有办法准确获取昵称和备注，因为微信自身的信息组织问题。
name, note, label = contact.Name.rsplit(" ", maxsplit=2)
try:
name, note, label = contact.Name.rsplit(" ", maxsplit=2)
except ValueError:
# 如果没有足够的空格，尝试用更少的分隔
parts = contact.Name.rsplit(" ", maxsplit=1) if " " in contact.Name else [contact.Name]
if len(parts) == 2:
name, note = parts
label = ""
else:
name = parts[0]
note = ""
label = ""

if name not in contact_set:
contacts = contacts._append({"昵称": name, "备注": note, "标签": label}, ignore_index=True)
contact_set.add(name)
Expand All @@ -228,7 +240,19 @@ def find_all_contacts(self) -> pd.DataFrame:
wheel_down()
for contact in auto.ListControl(Depth=7).GetChildren():
# 获取用户的昵称备注以及标签。注意这种方式没有办法准确获取昵称和备注，因为微信自身的信息组织问题。
name, note, label = contact.Name.rsplit(" ", maxsplit=2)
try:
name, note, label = contact.Name.rsplit(" ", maxsplit=2)
except ValueError:
# 如果没有足够的空格，尝试用更少的分隔
parts = contact.Name.rsplit(" ", maxsplit=1) if " " in contact.Name else [contact.Name]
if len(parts) == 2:
name, note = parts
label = ""
else:
name = parts[0]
note = ""
label = ""

if name not in contact_set:
contacts = contacts._append({"昵称": name, "备注": note, "标签": label}, ignore_index=True)
contact_set.add(name)
Expand Down