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Saurabh - Solution for Complex Assignment #16

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254 changes: 254 additions & 0 deletions Saurabh_complex_assignment.ipynb
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{
"cells": [
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"id": "JoMbQLjK3uHZ"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"<class 'complex'>\n",
"55227240\n"
]
}
],
"source": [
"#Declare a complex number and store it in a variable. \n",
"\n",
"a= 5+ 6j\n",
"\n",
"#Check the type and print the id of the same.\n",
"print(type(a))\n",
"print(id(a))\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"id": "6N6Ee4BU33jk"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"(7+9j)\n",
"(-3+1j)\n",
"(-10+33j)\n",
"(0.7317073170731708+0.41463414634146345j)\n",
"(38.470898411503946+4.625946953361943j)\n"
]
}
],
"source": [
"#Arithmatic Operations on complex number\n",
"#Take two different complex number.\n",
"#Store them in two different variables.\n",
"\n",
"first = 2+5j\n",
"second = 5+4j\n",
"\n",
"#Do below operations on them:-\n",
"\n",
" #Find sum of both numbers\n",
"\n",
"print(first+second)\n",
" \n",
" #Find differce between them\n",
"\n",
"print(first-second)\n",
" \n",
" #Find the product of both numbers.\n",
" \n",
"print(first*second)\n",
" \n",
" #Find value after dividing first num with second number\n",
" \n",
"print(first/second)\n",
" \n",
" #Find the result of first num to the power of second number.\n",
"\n",
"print(first ** second)\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"id": "xhkdg7LD352y"
},
"outputs": [],
"source": [
"#Comparison Operation not applicable between instance of complex values\n",
"#Object reusability concept is not applicable on complex numebr\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": 8,
"metadata": {
"id": "4lzPH2sb38KM"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"False\n",
"True\n"
]
}
],
"source": [
"#Equality Operator\n",
"#Take two different complex numbers.\n",
"\n",
"x= 7+9j\n",
"y= 8+4j\n",
"#Store them in two different variables.\n",
"#Equuate them using equality operator (==, !=)\n",
"\n",
"print(x==y)\n",
"print(x!=y)\n",
"#Observe the output(return type should be boolean)\n",
"\n",
"\n",
"\n",
"\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": 9,
"metadata": {
"id": "EDEl19UD3_tr"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"(20+30j)\n",
"0j\n",
"0j\n",
"0j\n",
"(10+20j)\n",
"(20+30j)\n",
"(20+30j)\n",
"0j\n",
"False\n",
"True\n"
]
}
],
"source": [
"#Logical operators\n",
"#Observe the output of below code\n",
"#Cross check the output manually\n",
"\n",
"print(10+20j and 20+30j) #20+30j #----------------------------------------->Output is 20+30j\n",
"print(0+0j and 20+30j) #0+0j #----------------------------------------->Output is 0j\n",
"print(20+30j and 0+0j) #0+0j #----------------------------------------->Output is 0j\n",
"print(0+0j and 0+0j) #0+0j #----------------------------------------->Output is 0j\n",
"\n",
"print(10+20j or 20+30j) #10+20j #----------------------------------------->Output is 10+20j\n",
"print(0+0j or 20+30j) #20+30j #----------------------------------------->Output is 20+30j\n",
"print(20+30j or 0+0j) #20+30j #----------------------------------------->Output is 20+30j\n",
"print(0+0j or 0+0j) #0+0j #----------------------------------------->Output is 0j\n",
"\n",
"print(not 10+20j) #False #----------------------------------------->Output is False\n",
"print(not 0+0j) #True #----------------------------------------->Output is True"
]
},
{
"cell_type": "code",
"execution_count": 10,
"metadata": {
"id": "4ifueKbP4Br1"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"False\n",
"True\n"
]
}
],
"source": [
"#What is the output of expression inside print statement. Cross check before running the program.\n",
"a = 10+20j\n",
"b = 10+20j\n",
"print(a is b) #False #True or False?\n",
"print(a is not b) #True #True or False?\n"
]
},
{
"cell_type": "code",
"execution_count": 11,
"metadata": {
"id": "TxMbr5jQ4Dwl"
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"True\n",
"True\n",
"True\n",
"True\n",
"True\n",
"True\n"
]
}
],
"source": [
"#Membership operation\n",
"#in, not in are two membership operators and it returns boolean value\n",
"\n",
"print('2.7' in 'Python2.7.8') #True\n",
"print(10+20j in [10,10.20,10+20j,'Python']) #True\n",
"print(10+20j in (10,10.20,10+20j,'Python')) #True\n",
"print(30+40j in {1,20.30,30+40j}) #True\n",
"print(30+40j in {1:100, 2.3:200, 30+40j:300}) #True\n",
"print(10 in range(20)) #True"
]
}
],
"metadata": {
"colab": {
"name": "Complex_Assignement.ipynb",
"provenance": []
},
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
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"language_info": {
"codemirror_mode": {
"name": "ipython",
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"file_extension": ".py",
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