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@sourcery-ai sourcery-ai bot commented Nov 30, 2023

Branch master refactored by Sourcery.

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@sourcery-ai sourcery-ai bot requested a review from strickvl November 30, 2023 08:54
total = 0
for char in string_num:
total += int(char) ** len(string_num)
total = sum(int(char) ** len(string_num) for char in string_num)
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Function is_armstrong_number refactored with the following changes:


grains_val = 1
for num in range(1, number):
for _ in range(1, number):
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Function square refactored with the following changes:

Comment on lines -2 to +4
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
return True
return False
return True
else:
if year % 4 != 0:
return False
return year % 400 == 0 if year % 100 == 0 else True
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Function is_leap_year refactored with the following changes:

return True
else:
return False
return len(abset) == 26
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Function is_pangram refactored with the following changes:

for val in range(1, number):
if number % val == 0:
total += val
total = sum(val for val in range(1, number) if number % val == 0)
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Function classify refactored with the following changes:

Comment on lines -11 to +12
self.area_code = self.number[0:3]
if self.area_code[0] == "0" or self.area_code[0] == "1":
self.area_code = self.number[:3]
if self.area_code[0] in ["0", "1"]:
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Function PhoneNumber.__init__ refactored with the following changes:

Comment on lines -21 to -29
startidx = 0
result = []
while startidx < len(strand):
for startidx in range(0, len(strand), 3):
codon = strand[startidx:startidx + 3]
if codon in STOP_CODONS:
return result
else:
result.append(CODON_TO_PROTEIN[codon])
startidx += 3
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Function proteins refactored with the following changes:

return False

return True
return 0 not in sides and a + b >= c and b + c >= a and a + c >= b
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Function is_triangle refactored with the following changes:

Comment on lines -34 to +38
if start_verse == 1:
pieces = [start] + ["a Partridge in a Pear Tree."]
else:
pieces = [start] + LIST[-start_verse:]
return pieces
return (
[start] + ["a Partridge in a Pear Tree."]
if start_verse == 1
else [start] + LIST[-start_verse:]
)
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Function recite refactored with the following changes:

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PR Type: Refactoring

Summary of PR: This PR introduces a series of refactoring changes aimed at simplifying and optimizing the codebase. It includes the use of list comprehensions, simplification of conditional statements, and the removal of unnecessary variables and loops.

General PR suggestions

  • Ensure that refactored logic accurately reflects the original intent and rules, especially in cases like the leap year calculation where the logic has been significantly altered.
  • When simplifying expressions, particularly with mathematical operations, consider if there is a more efficient way to achieve the same result, such as using direct mathematical formulas instead of loops.
  • Review the changes for any potential logical errors introduced during refactoring, such as the triangle inequality condition, to maintain the correctness of the program.
  • While the refactoring has generally improved readability and performance, it's important to validate that the changes have not introduced any regressions or altered the behavior of the code in unintended ways.

Your trial expires on December 14, 2023. Please email tim@sourcery.ai to continue using Sourcery ✨

else:
pieces = [start] + LIST[-start_verse:]
return pieces
return (
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suggestion (llm): Consider using a ternary expression directly in the return statement for improved readability.

Suggested change
return (
return [start] + (['a Partridge in a Pear Tree.'] if start_verse == 1 else LIST[-start_verse:])

else:
if year % 4 != 0:
return False
return year % 400 == 0 if year % 100 == 0 else True
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issue (llm): The refactored leap year check is incorrect. It will return True for all years not divisible by 100, which is not the correct leap year rule.

Suggested change
return year % 400 == 0 if year % 100 == 0 else True
return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

return False

return True
return 0 not in sides and a + b >= c and b + c >= a and a + c >= b
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issue (llm): The triangle inequality check should use strict inequality '>' rather than '>=' to ensure that the sum of the lengths of any two sides must be greater than the length of the remaining side.

Suggested change
return 0 not in sides and a + b >= c and b + c >= a and a + c >= b
return 0 not in sides and a + b > c and b + c > a and a + c > b

startidx = 0
result = []
while startidx < len(strand):
for startidx in range(0, len(strand), 3):
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praise (llm): Good job on simplifying the loop for iterating over the codons using a range with a step of 3.


grains_val = 1
for num in range(1, number):
for _ in range(1, number):
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suggestion (llm): Instead of using a loop to calculate the number of grains, consider using a direct mathematical expression for better performance.

Suggested change
for _ in range(1, number):
return 2 ** (number - 1)

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